Text::Text(InsetText * owner, bool use_default_layout)
- : owner_(owner), autoBreakRows_(false), undo_counter_(0)
+ : owner_(owner), autoBreakRows_(false)
{
pars_.push_back(Paragraph());
Paragraph & par = pars_.back();
Text::Text(InsetText * owner, Text const & text)
- : owner_(owner), autoBreakRows_(text.autoBreakRows_), undo_counter_(0)
+ : owner_(owner), autoBreakRows_(text.autoBreakRows_)
{
pars_ = text.pars_;
ParagraphList::iterator const end = pars_.end();
{
Paragraph & par = cur.paragraph();
- // Here we call finishUndo for every 20 characters inserted.
- // This is from my experience how emacs does it. (Lgb)
- if (undo_counter_ < 20) {
- ++undo_counter_;
- } else {
- cur.finishUndo();
- undo_counter_ = 0;
- }
-
// register word if a non-letter was entered
if (cur.pos() > 1
&& !par.isWordSeparator(cur.pos() - 2)
#include "support/debug.h"
#include "support/gettext.h"
#include "support/lassert.h"
+#include "support/lyxtime.h"
#include <algorithm>
#include <deque>
bool lc, size_t gid) :
kind(kin), cur_before(cb), cell(cel), from(fro), end(en),
pars(pl), array(ar), bparams(0),
- lyx_clean(lc), group_id(gid)
+ lyx_clean(lc), group_id(gid), time(current_time())
{
}
///
bool lc, size_t gid) :
kind(ATOMIC_UNDO), cur_before(cb), cell(), from(0), end(0),
pars(0), array(0), bparams(new BufferParams(bp)),
- lyx_clean(lc), group_id(gid)
+ lyx_clean(lc), group_id(gid), time(current_time())
{
}
///
- UndoElement(UndoElement const & ue)
+ UndoElement(UndoElement const & ue) : time(current_time())
{
kind = ue.kind;
cur_before = ue.cur_before;
bool lyx_clean;
/// the element's group id
size_t group_id;
+ /// timestamp
+ time_t time;
private:
/// Protect construction
UndoElement();
&& samePar(stack.top().cell, cell)
&& stack.top().kind == kind
&& stack.top().from == from
- && stack.top().end == end) {
+ && stack.top().end == end
+ && stack.top().cur_after == cur_before
+ && current_time() - stack.top().time <= 2) {
// reset cur_after; it will be filled correctly by endUndoGroup.
stack.top().cur_after = CursorData();
+ // update the timestamp of the undo element
+ stack.top().time = current_time();
return;
}