Make doExport() helper private

One declaration of doExport() was not used, and the other one was only used by
Buffer, so make it private since returning the exported file name is a bit
strange if it can also appear as input argument.

diff --git a/src/Buffer.h b/src/Buffer.h
index ad6aeb8deb50bf057a0751bae84ede033e7a96a0..97975f12c472a975c3b1ca79ba47ff73b680b053 100644 (file)
--- a/src/Buffer.h
+++ b/src/Buffer.h
@@ -643,20 +643,17 @@ public:
        ///
        ExportStatus doExport(std::string const & target, bool put_in_tempdir) const;
        ///
-       ExportStatus doExport(std::string const & target, bool put_in_tempdir,
-               std::string & result_file) const;
-       ///
        ExportStatus preview(std::string const & format) const;
 
 private:
+       ///
+       ExportStatus doExport(std::string const & target, bool put_in_tempdir,
+               std::string & result_file) const;
        /// target is a format name optionally followed by a space
        /// and a destination file-name
        ExportStatus doExport(std::string const & target, bool put_in_tempdir,
                bool includeall, std::string & result_file) const;
        ///
-       ExportStatus doExport(std::string const & target, bool put_in_tempdir,
-               bool includeall) const;
-       ///
        ExportStatus preview(std::string const & format, bool includeall = false) const;
        ///
        void setMathFlavor(OutputParams & op) const;