\endcode, not \code
os << c;
\endcode . The latter will not output the character, but the code point
- as number. This is because we can't overload operator<< (our character
- type is not a real type but a typedef). Narrow characters of type char
- can be output as usual.
+ as number if USE_WCHAR_T is not defined. This is because we can't overload
+ operator<< (our character type is not always a real type but sometimes a
+ typedef). Narrow characters of type char can be output as usual.
*/
typedef std::basic_ostream<char_type> odocstream;
they were iomanip's to ensure that the next output will start at the
beginning of a line. Using "breakln", a '\n' char will be output if needed,
while using "safebreakln", "%\n" will be output if needed.
+ The class also records the last output character.
*/
class otexstream {
///
otexstream(odocstream & os, TexRow & texrow)
: os_(os), texrow_(texrow),
- canbreakline_(false), protectspace_(false) {}
+ canbreakline_(false), protectspace_(false), lastchar_(0) {}
///
odocstream & os() { return os_; }
///
void protectSpace(bool protectspace) { protectspace_ = protectspace; }
///
bool protectSpace() const { return protectspace_; }
+ ///
+ void lastChar(char_type const & c) { lastchar_ = c; }
+ ///
+ char_type lastChar() const { return lastchar_; }
private:
///
odocstream & os_;
bool canbreakline_;
///
bool protectspace_;
+ ///
+ char_type lastchar_;
};
/// Helper structs for breaking a line
///
otexstream & operator<<(otexstream &, docstring const &);
///
+otexstream & operator<<(otexstream &, std::string const &);
+///
otexstream & operator<<(otexstream &, char const *);
///
otexstream & operator<<(otexstream &, char);