case SPACE:
// those elements contain only one position. Round to
// the closest side.
- if (x > full_width()) {
+ if (x > (full_width() + 1) / 2) {
x = int(full_width());
i = !isRTL();
} else {
x = 0;
i = isRTL();
}
-
}
//lyxerr << "=> p=" << pos + i << " x=" << x << endl;
return pos + i;
sel_beg(-1), sel_end(-1),
begin_margin_sel(false), end_margin_sel(false),
changed_(false), crc_(0),
- pit_(0), pos_(0), end_(0), right_boundary_(false), flushed_(false)
+ pit_(0), pos_(0), end_(0),
+ right_boundary_(false), flushed_(false), rtl_(false)
{}
// If the paragraph itself is RTL, reverse everything
if (rtl_par)
reverse(elements_.begin(), elements_.end());
+ rtl_ = rtl_par;
+}
+
+Row::const_iterator const
+Row::findElement(pos_type const pos, bool const boundary, double & x) const
+{
+ /**
+ * When boundary is true, position i is in the row element (pos, endpos)
+ * if
+ * pos < i <= endpos
+ * whereas, when boundary is false, the test is
+ * pos <= i < endpos
+ * The correction below allows to handle both cases.
+ */
+ int const boundary_corr = (boundary && pos) ? -1 : 0;
+
+ x = left_margin;
+
+ /** Early return in trivial cases
+ * 1) the row is empty
+ * 2) the position is the left-most position of the row; there
+ * is a quirk here however: if the first element is virtual
+ * (end-of-par marker for example), then we have to look
+ * closer
+ */
+ if (empty()
+ || (pos == begin()->left_pos() && !boundary
+ && !begin()->isVirtual()))
+ return begin();
+
+ Row::const_iterator cit = begin();
+ for ( ; cit != end() ; ++cit) {
+ /** Look whether the cursor is inside the element's
+ * span. Note that it is necessary to take the
+ * boundary into account, and to accept virtual
+ * elements, which have pos == endpos.
+ */
+ if (pos + boundary_corr >= cit->pos
+ && (pos + boundary_corr < cit->endpos || cit->isVirtual())) {
+ x += cit->pos2x(pos);
+ break;
+ }
+ x += cit->full_width();
+ }
+
+ if (cit == end())
+ --cit;
+
+ return cit;
}
+
} // namespace lyx