#include "BufferParams.h"
#include "Changes.h"
+#include "Font.h"
#include "insets/InsetText.h"
#include <boost/next_prior.hpp>
-#include <cmath>
-
using namespace std;
using namespace lyx::support;
class DocPair {
public:
- DocPair() {}
+ DocPair()
+ {}
DocPair(DocIterator o_, DocIterator n_)
: o(o_), n(n_)
{}
- bool operator!=(DocPair const & rhs) {
+ bool operator!=(DocPair const & rhs)
+ {
// this might not be intuitive but correct for our purpose
return o != rhs.o && n != rhs.n;
}
{}
/// Returns the from pair
- DocPair from() const { return DocPair(o.from, n.from); }
+ DocPair from() const
+ {
+ return DocPair(o.from, n.from);
+ }
/// Returns the to pair
- DocPair to() const { return DocPair(o.to, n.to); }
+ DocPair to() const
+ {
+ return DocPair(o.to, n.to);
+ }
DocRange o;
DocRange n;
template<class T>
class compl_vector {
public:
- compl_vector() {}
+ compl_vector()
+ {}
void reset(T const & def)
{
{}
///
- ~Impl() {}
+ ~Impl()
+ {}
// Algorithm to find the shortest edit string. This algorithm
// only needs a linear amount of memory (linear with the sum
bool abort_;
///
- QString status() {
+ QString status()
+ {
QString status;
status += toqstr("recursion level:") + " " + QString::number(recursion_level_)
+ " " + toqstr("differences:") + " " + QString::number(D_);
/// around the middle snake.
void diff_i(DocRangePair const & rp);
- /// Processes the splitted chunks. It either adds them as deleted,
+ /// Processes the split chunks. It either adds them as deleted,
/// as added, or call diff_i for further processing.
void diffPart(DocRangePair const & rp);
}
-static bool equal(DocIterator & o, DocIterator & n) {
+static bool equal(DocIterator & o, DocIterator & n)
+{
+ // Explicitly check for this, so we won't call
+ // Paragraph::getChar for the last pos.
+ bool const o_lastpos = o.pos() == o.lastpos();
+ bool const n_lastpos = n.pos() == n.lastpos();
+ if (o_lastpos || n_lastpos)
+ return o_lastpos && n_lastpos;
+
Paragraph const & old_par = o.text()->getPar(o.pit());
Paragraph const & new_par = n.text()->getPar(n.pit());
// Where do we take the step from ?
int const kk = vertical_step ? k + 1 : k - 1;
DocPair p(op[kk], np[kk]);
+ DocPair const s(os[kk], ns[kk]);
// If D==0 we simulate a vertical step from (0,-1) by doing nothing.
if (D != 0) {
ns[k] = p.n;
} else {
// Copy last snake from the previous step
- os[k] = os[kk];
- ns[k] = ns[kk];
+ os[k] = s.o;
+ ns[k] = s.n;
}
//Record new position
ors.reset(DocIterator());
nrs.reset(DocIterator());
+ // In the formula below, the "+ 1" ensures we round like ceil()
+ int const D_max = (M_ + N_ + 1)/2;
// D is the number of horizontal and vertical steps, i.e.
// different characters in the old and new chunk.
- int const D_max = ceil(((double)M_ + N_)/2);
for (int D = 0; D <= D_max; ++D) {
// to be used in the status messages
D_ = D;
return 2 * D - odd_offset_;
}
}
+ if (abort_)
+ return 0;
}
}
}
processSnake(snake);
// Start the recursive algorithm
- diff_i(rp);
+ DocRangePair rp_new(from, rp.to());
+ if (!rp_new.o.empty() || !rp_new.n.empty())
+ diff_i(rp_new);
for (pit_type p = 0; p < (pit_type)dest_pars_->size(); ++p) {
(*dest_pars_)[p].setBuffer(const_cast<Buffer &>(*dest_buf));
void Compare::Impl::diff_i(DocRangePair const & rp)
{
+ if (abort_)
+ return;
+
// The middle snake
DocPair middle_snake;