namespace {
-// gets the "prename" and "family name" from an author-type string
-pair<docstring, docstring> nameParts(docstring const & name)
+// Remove placeholders from names
+docstring renormalize(docstring const & input)
{
- if (name.empty())
- return make_pair(docstring(), docstring());
+ docstring res = subst(input, from_ascii("$$space!"), from_ascii(" "));
+ return subst(res, from_ascii("$$comma!"), from_ascii(","));
+}
+
+
+// Split the surname into prefix ("von-part") and family name
+pair<docstring, docstring> parseSurname(docstring const & sname)
+{
+ // Split the surname into its tokens
+ vector<docstring> pieces = getVectorFromString(sname, from_ascii(" "));
+ if (pieces.size() < 2)
+ return make_pair(docstring(), sname);
+
+ // Now we look for pieces that begin with a lower case letter.
+ // All except for the very last token constitute the "von-part".
+ docstring prefix;
+ vector<docstring>::const_iterator it = pieces.begin();
+ vector<docstring>::const_iterator const en = pieces.end();
+ bool first = true;
+ for (; it != en; ++it) {
+ if ((*it).empty())
+ continue;
+ // If this is the last piece, then what we now have is
+ // the family name, notwithstanding the casing.
+ if (it + 1 == en)
+ break;
+ char_type const c = (*it)[0];
+ // If the piece starts with a upper case char, we assume
+ // this is part of the surname.
+ if (!isLower(c))
+ break;
+ // Nothing of the former, so add this piece to the prename
+ if (!first)
+ prefix += " ";
+ else
+ first = false;
+ prefix += *it;
+ }
+
+ // Reconstruct the family name.
+ // Note that if we left the loop with because it + 1 == en,
+ // then this will still do the right thing, i.e., make surname
+ // just be the last piece.
+ docstring surname;
+ first = true;
+ for (; it != en; ++it) {
+ if (!first)
+ surname += " ";
+ else
+ first = false;
+ surname += *it;
+ }
+ return make_pair(prefix, surname);
+}
+
- // first we look for a comma, and take the last name to be everything
- // preceding the right-most one, so that we also get the "jr" part.
+struct name_parts {
+ docstring surname;
+ docstring prename;
+ docstring suffix;
+ docstring prefix;
+};
+
+
+// gets the name parts (prename, surname, prefix, suffix) from an author-type string
+name_parts nameParts(docstring const & iname)
+{
+ name_parts res;
+ if (iname.empty())
+ return res;
+
+ // First we check for goupings (via {...}) and replace blanks and
+ // commas inside groups with temporary placeholders
+ docstring name;
+ int gl = 0;
+ docstring::const_iterator p = iname.begin();
+ while (p != iname.end()) {
+ // count grouping level
+ if (*p == '{')
+ ++gl;
+ else if (*p == '}')
+ --gl;
+ // generate string with probable placeholders
+ if (*p == ' ' && gl > 0)
+ name += from_ascii("$$space!");
+ else if (*p == ',' && gl > 0)
+ name += from_ascii("$$comma!");
+ else
+ name += *p;
+ ++p;
+ }
+
+ // Now we look for a comma, and take the last name to be everything
+ // preceding the right-most one, so that we also get the name suffix
+ // (aka "jr" part).
vector<docstring> pieces = getVectorFromString(name);
- if (pieces.size() > 1)
- // whether we have a jr. part or not, it's always
- // the first and last item (reversed)
- return make_pair(pieces.back(), pieces.front());
+ if (pieces.size() > 1) {
+ // Whether we have a name suffix or not, the prename is
+ // always last item
+ res.prename = renormalize(pieces.back());
+ // The family name, conversely, is always the first item.
+ // However, it might contain a prefix (aka "von" part)
+ docstring const sname = pieces.front();
+ res.prefix = renormalize(parseSurname(sname).first);
+ res.surname = renormalize(parseSurname(sname).second);
+ // If we have three pieces (the maximum allowed by BibTeX),
+ // the second one is the name suffix.
+ if (pieces.size() > 2)
+ res.suffix = renormalize(pieces.at(1));
+ return res;
+ }
- // OK, so now we want to look for the last name. We're going to
- // include the "von" part. This isn't perfect.
+ // OK, so now we want to look for the last name.
// Split on spaces, to get various tokens.
pieces = getVectorFromString(name, from_ascii(" "));
- // unusual not to have a space, but could happen
- if (pieces.size() < 2)
- return make_pair(from_ascii(""), name);
- // If we get two, assume the last one is the last name
- if (pieces.size() == 2)
- return make_pair(pieces.front(), pieces.back());
+ // No space: Only a family name given
+ if (pieces.size() < 2) {
+ res.surname = renormalize(pieces.back());
+ return res;
+ }
+ // If we get two pieces, assume "prename surname"
+ if (pieces.size() == 2) {
+ res.prename = renormalize(pieces.front());
+ res.surname = renormalize(pieces.back());
+ return res;
+ }
- // Now we look for the first token that begins with
- // a lower case letter or an opening group {.
+ // More than 3 pieces: A name prefix (aka "von" part) might be included.
+ // We look for the first piece that begins with a lower case letter
+ // (which is the name prefix, if it is not the last token) or the last token.
docstring prename;
vector<docstring>::const_iterator it = pieces.begin();
vector<docstring>::const_iterator const en = pieces.end();
if ((*it).empty())
continue;
char_type const c = (*it)[0];
- if (isLower(c) || c == '{')
+ // If the piece starts with a lower case char, we assume
+ // this is the name prefix and thus prename is complete.
+ if (isLower(c))
break;
- // if this is the last time through the loop, then
- // what we now have is the last name, so we do not want
- // to add that to the prename.
+ // Same if this is the last piece, which is always the surname.
if (it + 1 == en)
break;
- // add this piece to the prename
+ // Nothing of the former, so add this piece to the prename
if (!first)
prename += " ";
else
prename += *it;
}
- // reconstruct the family name
- // note that if we left the loop with because it + 1 == en,
+ // Now reconstruct the family name and strip the prefix.
+ // Note that if we left the loop because it + 1 == en,
// then this will still do the right thing, i.e., make surname
// just be the last piece.
docstring surname;
first = false;
surname += *it;
}
- return make_pair(prename, surname);
+ res.prename = renormalize(prename);
+ res.prefix = renormalize(parseSurname(surname).first);
+ res.surname = renormalize(parseSurname(surname).second);
+ return res;
}
{
// re-constructs a name from name parts according
// to a given scheme
- docstring const prename = nameParts(name).first;
- docstring const surname = nameParts(name).second;
- docstring result = from_ascii(scheme);
+ docstring const prename = nameParts(name).prename;
+ docstring const surname = nameParts(name).surname;
+ docstring const prefix = nameParts(name).prefix;
+ docstring const suffix = nameParts(name).suffix;
+ string res = scheme;
+ static regex const reg1("(.*)(\\{%prename%\\[\\[)([^\\]]+)(\\]\\]\\})(.*)");
+ static regex const reg2("(.*)(\\{%suffix%\\[\\[)([^\\]]+)(\\]\\]\\})(.*)");
+ static regex const reg3("(.*)(\\{%prefix%\\[\\[)([^\\]]+)(\\]\\]\\})(.*)");
+ smatch sub;
+ // Changing the first parameter of regex_match() may corrupt the
+ // second one. In this case we use the temporary string tmp.
+ if (regex_match(scheme, sub, reg1)) {
+ res = sub.str(1);
+ if (!prename.empty())
+ res += sub.str(3);
+ res += sub.str(5);
+ }
+ if (regex_match(res, sub, reg2)) {
+ string tmp = sub.str(1);
+ if (!suffix.empty())
+ tmp += sub.str(3);
+ res = tmp + sub.str(5);
+ }
+ if (regex_match(res, sub, reg3)) {
+ string tmp = sub.str(1);
+ if (!prefix.empty())
+ tmp += sub.str(3);
+ res = tmp + sub.str(5);
+ }
+ docstring result = from_ascii(res);
result = subst(result, from_ascii("%prename%"), prename);
result = subst(result, from_ascii("%surname%"), surname);
+ result = subst(result, from_ascii("%prefix%"), prefix);
+ result = subst(result, from_ascii("%suffix%"), suffix);
return result;
}
+vector<docstring> const getAuthors(docstring const & author)
+{
+ // We check for goupings (via {...}) and only consider " and "
+ // outside groups as author separator. This is to account
+ // for cases such as {{Barnes and Noble, Inc.}}, which
+ // need to be treated as one single family name.
+ // We use temporary placeholders in order to differentiate the
+ // diverse " and " cases.
+
+ // First, we temporarily replace all ampersands. It is rather unusual
+ // in author names, but can happen (consider cases such as "C \& A Corp.").
+ docstring iname = subst(author, from_ascii("&"), from_ascii("$$amp!"));
+ // Then, we temporarily make all " and " strings to ampersands in order
+ // to handle them later on a per-char level.
+ iname = subst(iname, from_ascii(" and "), from_ascii(" & "));
+ // Now we traverse through the string and replace the "&" by the proper
+ // output in- and outside groups
+ docstring name;
+ int gl = 0;
+ docstring::const_iterator p = iname.begin();
+ while (p != iname.end()) {
+ // count grouping level
+ if (*p == '{')
+ ++gl;
+ else if (*p == '}')
+ --gl;
+ // generate string with probable placeholders
+ if (*p == '&') {
+ if (gl > 0)
+ // Inside groups, we output "and"
+ name += from_ascii("and");
+ else
+ // Outside groups, we output a separator
+ name += from_ascii("$$namesep!");
+ }
+ else
+ name += *p;
+ ++p;
+ }
+
+ // re-insert the literal ampersands
+ name = subst(name, from_ascii("$$amp!"), from_ascii("&"));
+
+ // Now construct the actual vector
+ return getVectorFromString(name, from_ascii(" $$namesep! "));
+}
+
+
bool multipleAuthors(docstring const author)
{
- vector<docstring> const authors =
- getVectorFromString(author, from_ascii(" and "));
- return authors.size() > 1;
+ return getAuthors(author).size() > 1;
}
continue;
}
- // we just ignore braces
+ // Change text mode accents in the form
+ // {\v a} to \v{a} (see #9340).
+ // FIXME: This is a sort of mini-tex2lyx.
+ // Use the real tex2lyx instead!
+ static lyx::regex const tma_reg("^\\{\\\\[bcCdfGhHkrtuUv]\\s\\w\\}");
+ if (lyx::regex_search(to_utf8(val), tma_reg)) {
+ val = val.substr(1);
+ val.replace(2, 1, from_ascii("{"));
+ continue;
+ }
+
+ // Apart from the above, we just ignore braces
if (ch == '{' || ch == '}') {
val = val.substr(1);
continue;
return ret;
}
-} // anon namespace
+} // namespace
//////////////////////////////////////////////////////////////////////
}
-docstring const BibTeXInfo::getAuthorList(Buffer const * buf,
- docstring const & author, bool const full, bool const forceshort,
+docstring const BibTeXInfo::getAuthorList(Buffer const * buf,
+ docstring const & author, bool const full, bool const forceshort,
bool const allnames, bool const beginning) const
{
// Maxnames treshold depend on engine
if (author.empty())
return author;
- // FIXME Move this to a separate routine that can
- // be called from elsewhere.
- //
// OK, we've got some names. Let's format them.
- // Try to split the author list on " and "
- vector<docstring> const authors =
- getVectorFromString(author, from_ascii(" and "));
+ // Try to split the author list
+ vector<docstring> const authors = getAuthors(author);
docstring retval;
: " and ";
string firstnameform =
buf ? buf->params().documentClass().getCiteMacro(engine_type, "!firstnameform")
- : "%surname%, %prename%";
+ : "{%prefix%[[%prefix% ]]}%surname%{%suffix%[[, %suffix%]]}{%prename%[[, %prename%]]}";
if (!beginning)
firstnameform = buf ? buf->params().documentClass().getCiteMacro(engine_type, "!firstbynameform")
- : "%prename% %surname%";
+ : "%prename% {%prefix%[[%prefix% ]]}%surname%{%suffix%[[, %suffix%]]}";
string othernameform = buf ? buf->params().documentClass().getCiteMacro(engine_type, "!othernameform")
- : "%surname%, %prename%";
+ : "{%prefix%[[%prefix% ]]}%surname%{%suffix%[[, %suffix%]]}{%prename%[[, %prename%]]}";
if (!beginning)
othernameform = buf ? buf->params().documentClass().getCiteMacro(engine_type, "!otherbynameform")
- : "%prename% %surname%";
+ : "%prename% {%prefix%[[%prefix% ]]}%surname%{%suffix%[[, %suffix%]]}";
+ string citenameform = buf ? buf->params().documentClass().getCiteMacro(engine_type, "!citenameform")
+ : "{%prefix%[[%prefix% ]]}%surname%";
// Shorten the list (with et al.) if forceshort is set
// and the list can actually be shortened, else if maxcitenames
retval += (i == 0) ? constructName(*it, firstnameform)
: constructName(*it, othernameform);
else
- retval += nameParts(*it).second;
+ retval += constructName(*it, citenameform);
}
if (shorten) {
if (allnames)
retval = constructName(authors[0], firstnameform) + (buf ? buf->B_(etal) : from_ascii(etal));
else
- retval = nameParts(authors[0]).second + (buf ? buf->B_(etal) : from_ascii(etal));
+ retval = constructName(authors[0], citenameform) + (buf ? buf->B_(etal) : from_ascii(etal));
}
return convertLaTeXCommands(retval);
}
-} // anon namespace
+} // namespace
/* FIXME
Bug #9131 revealed an oddity in how we are generating citation information
-when more than one key is given. We end up building a longer and longer format
+when more than one key is given. We end up building a longer and longer format
string as we go, which we then have to re-parse, over and over and over again,
rather than generating the information for the individual keys and then putting
all of that together. We do that to deal with the way separators work, from what
}
};
-} // namespace anon
+} // namespace
vector<docstring> const BiblioInfo::getXRefs(BibTeXInfo const & data, bool const nested) const
if (xrefs.empty())
// no luck
return docstring();
- vector<docstring>::const_iterator it = xrefs.begin();
- vector<docstring>::const_iterator en = xrefs.end();
- for (; it != en; ++it) {
- BiblioInfo::const_iterator const xrefit = find(*it);
+ for (docstring const & xref : xrefs) {
+ BiblioInfo::const_iterator const xrefit = find(xref);
if (xrefit == end())
continue;
BibTeXInfo const & xref_data = xrefit->second;
BibTeXInfo const & data = it->second;
BibTeXInfoList xrefptrs;
vector<docstring> const xrefs = getXRefs(data);
- if (!xrefs.empty()) {
- vector<docstring>::const_iterator it = xrefs.begin();
- vector<docstring>::const_iterator en = xrefs.end();
- for (; it != en; ++it) {
- BiblioInfo::const_iterator const xrefit = find(*it);
- if (xrefit != end())
- xrefptrs.push_back(&(xrefit->second));
- }
+ for (docstring const & xref : getXRefs(data)) {
+ BiblioInfo::const_iterator const xrefit = find(xref);
+ if (xrefit != end())
+ xrefptrs.push_back(&(xrefit->second));
}
return data.getInfo(xrefptrs, buf, ci);
}
vector<BibTeXInfo const *> xrefptrs;
if (it != end()) {
data = it->second;
- vector<docstring> const xrefs = getXRefs(data);
- if (!xrefs.empty()) {
- vector<docstring>::const_iterator it = xrefs.begin();
- vector<docstring>::const_iterator en = xrefs.end();
- for (; it != en; ++it) {
- BiblioInfo::const_iterator const xrefit = find(*it);
- if (xrefit != end())
- xrefptrs.push_back(&(xrefit->second));
- }
+ for (docstring const & xref : getXRefs(data)) {
+ BiblioInfo::const_iterator const xrefit = find(xref);
+ if (xrefit != end())
+ xrefptrs.push_back(&(xrefit->second));
}
}
ret = data.getLabel(xrefptrs, buf, ret, ci, key + 1 != ken, i == 1);
}
-vector<docstring> const BiblioInfo::getCiteStrings(
+BiblioInfo::CiteStringMap const BiblioInfo::getCiteStrings(
vector<docstring> const & keys, vector<CitationStyle> const & styles,
Buffer const & buf, CiteItem const & ci) const
{
if (empty())
- return vector<docstring>();
+ return vector<pair<docstring,docstring>>();
string style;
- vector<docstring> vec(styles.size());
- for (size_t i = 0; i != vec.size(); ++i) {
+ CiteStringMap csm(styles.size());
+ for (size_t i = 0; i != csm.size(); ++i) {
style = styles[i].name;
- vec[i] = getLabel(keys, buf, style, ci);
+ csm[i] = make_pair(from_ascii(style), getLabel(keys, buf, style, ci));
}
- return vec;
+ return csm;
}
|| (lauth == rauth && lyear == ryear && ltitl < rtitl);
}
-}
+} // namespace
void BiblioInfo::collectCitedEntries(Buffer const & buf)