+ // assume now that the current element is not there
+ wid_brk -= brk.dim.wid;
+ /*
+ * Some Asian languages split lines anywhere (no notion of
+ * word). It seems that QTextLayout is not aware of this fact.
+ * See for reference:
+ * https://en.wikipedia.org/wiki/Line_breaking_rules_in_East_Asian_languages
+ *
+ * FIXME: Something shall be done about characters which are
+ * not allowed at the beginning or end of line.
+ */
+ bool const word_wrap = brk.font.language()->wordWrap();
+ // When there is text before the body part (think description
+ // environment), do not try to break.
+ if (brk.pos < keep)
+ continue;
+ /* We have found a suitable separable element. This is the common case.
+ * Try to break it cleanly (at word boundary) at a length that is both
+ * - less than the available space on the row
+ * - shorter than the natural width of the element, in order to enforce
+ * break-up.
+ */
+ if (brk.breakAt(min(w - wid_brk, brk.dim.wid - 2), !word_wrap)) {
+ /* if this element originally did not cause a row overflow
+ * in itself, and the remainder of the row would still be
+ * too large after breaking, then we will have issues in
+ * next row. Thus breaking does not help.
+ */
+ if (wid_brk + cit_brk->dim.wid < w
+ && dim_.wid - (wid_brk + brk.dim.wid) >= next_width) {
+ break;
+ }
+ end_ = brk.endpos;
+ /* after breakAt, there may be spaces at the end of the
+ * string, but they are not counted in the string length
+ * (QTextLayout feature, actually). We remove them, but do
+ * not change the end of the row, since spaces at row
+ * break are invisible.
+ */
+ brk.str = rtrim(brk.str);
+ brk.endpos = brk.pos + brk.str.length();
+ *cit_brk = brk;
+ dim_.wid = wid_brk + brk.dim.wid;
+ // If there are other elements, they should be removed.
+ elements_.erase(cit_brk + 1, end);
+ return true;
+ }
+ }
+
+ if (cit != beg && cit->type == VIRTUAL) {
+ // It is not possible to separate a virtual element from the
+ // previous one.
+ --cit;
+ wid -= cit->dim.wid;
+ }
+
+ if (cit != beg) {
+ // There is no usable separator, but several elements have
+ // been added. We can cut right here.
+ end_ = cit->pos;
+ dim_.wid = wid;
+ elements_.erase(cit, end);
+ return true;
+ }
+
+ /* If we are here, it means that we have not found a separator to
+ * shorten the row. Let's try to break it again, but not at word
+ * boundary this time.
+ */
+ if (cit->breakAt(w - wid, true)) {
+ end_ = cit->endpos;
+ // See comment above.
+ cit->str = rtrim(cit->str);
+ cit->endpos = cit->pos + cit->str.length();
+ dim_.wid = wid + cit->dim.wid;
+ // If there are other elements, they should be removed.
+ elements_.erase(next(cit, 1), end);
+ return true;